(900+2x+0.08x^2)/20

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Solution for (900+2x+0.08x^2)/20 equation: 


x in (-oo:+oo)

(0.08*x^2+2*x+900)/20 = 0

0.08*x^2+2*x+900 = 0

0.08*x^2+2*x+900 = 0

DELTA = 2^2-(0.08*4*900)

DELTA = -284

DELTA < 0

1 = 0

1/20 = 0

x belongs to the empty set

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